A1083 List Grades (25)(25 分)
Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.
Input Specification:
Each input file contains one test case. Each case is given in the following format:
Nname[1] ID[1] grade[1]name[2] ID[2] grade[2]... ...name[N] ID[N] grade[N]grade1 grade2
where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output "NONE" instead.
Sample Input 1:
4Tom CS000001 59Joe Math990112 89Mike CS991301 100Mary EE990830 9560 100
Sample Output 1:
Mike CS991301Mary EE990830Joe Math990112
Sample Input 2:
2Jean AA980920 60Ann CS01 8090 95
Sample Output 2:
NONE
AC代码
#include#include #include #include #define maxn 50struct Student { char name[11]; char id[11]; int grade;}stu[maxn];int cmp(const void*a, const void*b) {// struct Student*aa=(Student*)a;// struct Student*bb=(Student*)b; struct Student*aa=a; struct Student*bb=b; return aa->grade < bb->grade ? 1:-1;//为实现成绩降序,c++ 是>,c语言则是<,1<2返回正值,1==2返回0,1>2,返回负值 }int main() { int n, left, right; scanf("%d", &n); for(int i = 0; i < n; i++) { scanf("%s %s %d", stu[i].name, stu[i].id, &stu[i].grade); } scanf("%d%d", &left, &right); qsort(stu,n,sizeof(stu[0]), cmp); bool flag = false; for(int i = 0; i < n; i++) { if(stu[i].grade >= left && stu[i].grade <= right) { printf("%s %s\n", stu[i].name, stu[i].id); flag = true; } } if(flag == false) { printf("NONE\n"); } return 0;}